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What is an equation of a line passing through (3,3) and (4,7) show working
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Again, first find the slope using (y2-y1)/(x2-x1)
@Mhansen let x1= 3, y1 = 3, x2 = 4, y2 = 7
(7-3)/(4-3)
Yes I did that
what is the slope? Put that into point-intercept form, which is: y-y1=m(x-x1), where m is the slope, and x1/y1 is the x and y coordinate of one of the pairs of points given.
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Lets use the point (3,3). y-(3)=4(x-3) solve for y
*distribute the 4 first, though
Oh thx
post what you got
It should be in the form of y=mx+b
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