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Mathematics 24 Online
OpenStudy (anonymous):

Multiplying and Dividing Rational Expressions? https://media.glynlyon.com/g_alg01_2013/10/217.gif

OpenStudy (anonymous):

@whpalmer4

OpenStudy (anonymous):

\[ 3m-9 = 3(m-3) \]Also \[ m^2-9 = (m+3)(m-3) \]

OpenStudy (anonymous):

\[ 4m+8 = 4(m+2) \]

OpenStudy (anonymous):

So basically, I'm just factoring all of them.

OpenStudy (anonymous):

Can you factor \(m^2+5m+6\)?

OpenStudy (anonymous):

Do you have an idea of how to factor?

OpenStudy (anonymous):

\[ (m+a)(m+b) = m^2+am + bm+ab = m^2+(a+b)m+ab \]

OpenStudy (anonymous):

Think about \(ab = 6\) and \(a+b=5\)

OpenStudy (anonymous):

\( (2)(3) = 6 \) and \(2+3=5\). This means \((m+2)(m+3) = m^2+5m+6\)

OpenStudy (anonymous):

You will see that \((m+3)\) will cancel, so will \((m+2)\) and \((m-3)\).

OpenStudy (anonymous):

\[ \frac{3(m-3)}{4(m+2)}\cdot \frac{(m+2)(m+3)}{(m-3)(m+3)} = \frac{3\color{red}{\cancel{(m-3)}}}{4\cancel{(m+2)}}\cdot \frac{\cancel{(m+2)}\color{blue}{\cancel{(m+3)}}}{\color{red}{\cancel{(m-3)}}\color{blue}{\cancel{(m+3)}}} = \frac{3}{4} \]

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