Question

im lazy will get.What is the equation of the line that contains the points (3, –6) and (–3, 0)?

Answer 1

will get medal

Answer 2

I am too lazy to help

Answer 3

Given points are: (3, –6) =(x1, y1) and (–3, 0)=(x2, y2)
eQUATION OF LINE IN 2 POINT FORM IS GIVEN AS:

y-y1= m(x-x1)

m= (y1-y2)/(x1-x2) =(-6-0)/(3+3) =(-6)/(6) =-1
hence eq of line
y-y1= m(x-x1)
i.e. y-(-6)= -1(x-3)
i.e. y +6= -x+3
x+y = -3 is the required eq of the line