Question

A tube of tennis balls has the following measures: 4-inch diameter and a height of 8 inches. What is the surface area of the tube of tennis balls? (Use 3.14 for π.)

213.52 in.2
301.44 in.2
226.08 in.2
125.6 in.2

Answer 1

Cylinder Surface Area = 2*pi*r^2 + 2*pi*r*h

Just plug and chug!

Answer 2

Using the sketch above:
The area of the time is \(\pi r^2\), the area of the sides is \(2\pi rh\)
$$
\large{
SA=2\times\pi r^2+ 2\times \pi rh
}
$$

That's it!

Answer 3

You have a diameter of 4, so half of that is the radius = 2.