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How do you find the angle of a fired projectile given the initial velocity and the distance it travels?
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Use the formula for range!
so the y=vt-(1/2)gt^2 formula?
Not really.. haven't u derived the formula for range? if not so.. then.. u can do it conceptually.. consider the horizontal motion!
I haven't learned about derivations yet in math. But would it be something long the lines of \[y=(vsin(\theta))\frac{ x }{ v_x }-\frac{1}{2}g(\frac{ x }{ v_x })^2\]?
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