Question

Need help finding the integrand again, I tried 1/x but it's not working
@sylbot MEDALS

Answer 1

the problem here is your a and b values. To make this problem as simple as possible, select 6 as the "a". This makes 13 the "b". Then you can do 1/x.

Answer 2

is it too difficult to explain what would happen if I chose 10 and 17?

Answer 3

if you choose 10 as "a" ,then you need to make a function f(10+7k/n) equal to 1/(6+7k/n),
so the function would be 1/(x-4)
Plug it in and see for yourself, that 1/(10+7k/n - 4)= 1/(6+7k/n).
So if you want to choose 10 and 17, you would need 1/(x-4) as a function to make it work. It just makes it more difficult for no reason, but you can still do it.

Answer 4

thanks mate!