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OpenStudy (anonymous):
Do you want to foil it?
(x+4)(x+5) = (x*x)+(x*5)+(x*4)+(4*5)
OpenStudy (anonymous):
x=-5and -4
OpenStudy (anonymous):
it just asks to multiply
OpenStudy (anonymous):
To multiply, simply what I wrote down
OpenStudy (anonymous):
how would I correctly right that as in answer
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OpenStudy (anonymous):
it on mathlab
OpenStudy (anonymous):
Exponents with the highest answer first, so ex:
x^2+2x+1
OpenStudy (anonymous):
x^2 has exponent of 2, 2x has a exponent of 1 since 2x^1 = 2x, and 1 has an exponent of 1, but variables are written first
OpenStudy (anonymous):
On math lab, I would think has an exponent key, so it would show up as:
\[x^2+2x+1\] <- this is not the answer, this is what it would look like.
Simplify it, and what do you get?
OpenStudy (anonymous):
I got x^2+9x+20
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OpenStudy (anonymous):
That is correct
hero (hero):
Three ways to multiply binomials:
Example using distributive property:
(x + 3)(x + 1) = x(x + 1) + 3(x + 1)
= x^2 + x + 3x + 3
= x^2 + 4x + 3
Example using FOIL:
(x + 3)(x + 1) = (x*x) + (1*x) + (3*x) + (3*1)
= x^2 + x + 3x + 3
= x^2 + 4x + 3
Example using top down method:
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