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Mathematics 16 Online
OpenStudy (anonymous):

Simplify (√12-√6) (√6+√3). A) 2√3 B) 2√3 + 12 C) 2√3 - 12 D) √54

OpenStudy (anonymous):

Alright. So let's start out with expanding the whole thing. Could you do that? :)

OpenStudy (anonymous):

Like, √12 • √6 + √12 • √3 - √6 • √6 - √6 •√3 ?

OpenStudy (anonymous):

Yup :)

OpenStudy (anonymous):

Then we can simplify from there.

OpenStudy (anonymous):

Oh.. I know that the part with √6 •√6 equals 6, so it would be √12 •√6 + √12 • √3 - 6 - √6 • √3 , but I don't know where to go from there...

OpenStudy (anonymous):

Alright. What's 12 x 6? Similarly, what 12 x 3 and 6 x 3?

OpenStudy (anonymous):

12 x 6 = 72 12 x 3 = 36 6 x 3 = 18 So would it be √72 - √18 ?

OpenStudy (anonymous):

Nice! Alright. Do you know how to simplify square root 72 and square root 18? Like 18 would be 3 square root 2?

OpenStudy (anonymous):

Yeah, I think... So √72 would be 6√2 and, like you said, √18 wold be 3√2?

OpenStudy (paki):

it will be like... √72 - √18... = 6√ 2 - 3√2...

OpenStudy (anonymous):

Nice. :D Now you have like terms, and you can subtract. :)

OpenStudy (anonymous):

Thank you @anitasonia98 ! You're rad!

OpenStudy (anonymous):

Ah, thanks! :D

OpenStudy (phi):

btw, when multiplying square roots, instead of doing the multiplication it's often easier to write down factors and look for *pairs* thus √12 •√6 + √12 • √3 - 6 - √6 • √3 becomes √2 √6 √6 + √4 √3 √3 - 6 - √2 √3 √3 and 6 √2 + 2*3 - 6 -3 √2

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