Need help finding area of scalene triangle. Thanks! Medals for everyone!
I=x^2-x from 0 to 4. so 4^2-4 - 0^2+0 = 16-4=12
correct me if I'm wrong but wouldnt you just take the integral of that (giving you x^2-3x\4,0 and then plugging the numbers in you get 16-12 and the answer from then should be 4?
both wrong
Hint: Recall that |z| = z if z is nonnegative, and |z| = -z if z is negative. Use this fact to remove the absolute value from the integrand, splitting the integral over two separate ranges of integration if needed.
oh poop yes that makes sense your'e going to want to separate the integral to where it is positive and negative and by setting 2x-3= 0 we can see that x = 3/2 so you're going to do one integral of that equation from 0 to 3/2 and then another from 3/2 to 4 make them both positive and then add them
lemme know if you need help with the actual integration part
yeah i do, thanks
yay math!
yeah math is cool
okay when you take the integral which is x^2-3x you're going to plug in your new limits of 0 and 3/2 which give you the value of -9/4 but since were taking the absolute value that makes it positive. the second integral from 3/2 to 4 gives you 25/4 adding the two you get 34/4 or 17/2 hopefully. sorry this is all mental math since i have no paper
correct thanks for the help, ill look over your notes
awesome. I you need more help I'm procrastinating studying for my nuclear chemistry test so I'l be here lol
to each to his own..i couldn't do that stuff, im an econ major. have fun mate
you need calc for econ?
yeah i started a little late on the math cause i wasn't sure what i was going to major in. Im a sophomore but ill be finishing calc 3 by this fall so i can take an actual stats course as opposed to those "stats workshop" type classes
Ahh I gotcha. I'm in calc 3 at Purdue at the moment. Have fun! and have a great day!
you to bro, go spartans
too*
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