what are solutions to this equation 2x^2+6x=20 the options r -5,-10,-2,1,2,20

Question

what are solutions to this equation 2x^2+6x=20      the options r -5,-10,-2,1,2,20

mathmale · Answer

I see immediately that we could simplify the work involved by dividing every term of this equation by 2.  Would you do that , please?

solomonzelman · Answer

2x^2+6x=20 
2x^2+6x-20 =0
2(x^2+3x-10) =0
x^2+3x-10 =0

(think of 5 and -2 )

mathmale · Answer

As a next step, please consolidate all of the terms on the left side.  To do this, please subtract 10 from both sides.  Type out the result here.

acxbox22 · Answer

divide everything by 2
complete the square

anonymous · Answer

Hint: its two of the options that are given to you

acxbox22 · Answer

nice hint

anonymous · Answer

Thank you

acxbox22 · Answer

x^2+3x=10
x^2+3x+2.25=12.25
(x+1.5)^2=12.25
find squareroot of each
$$x+1.5=\pm3.5$$

acxbox22 · Answer

x=3.5-1.5
x=-3.5-1.5
x=2,-5