verify cos(a+b)cos(a-b) = cos^2b-sin^a
do you want to PROVE the sum formula?
http://openstudy.com/users/enlightened#/updates/534ad228e4b0dfc5ac71df10 looks like you asked that question here and freckles gave you great advice
and difference formula*
I think the distributive property answer is really simple
i am going to ask you the same question freckles asked can you give me what cos(a+b) is equal to and what cos(a-b) is equal to?
Hint: cos(a+b) = cos(a+b) because of the property x =x
LOL I think he means in terms of cos(a) and cos(b) and sin(a) and sin(b)
@Enlightened if you want my help can you please answer my question?
oh i'm sorry, yeah it's in terms of cos a and cos b and sina and sinb, there are no actual values to them.
...those are the terms, you must relate them.
@enlightened will you answer my question. I'm trying to get you to use the sum and difference identities on cos(a+b) and cos(a-b) you have not done that yet.
cos(a+b)=cos(a)cos(b)-sin(a)sin(b) cos(a-b)=cos(a)cos(b)+sin(a)sin(b)
@myininaya there it is ^
great now multiply those
what do i multiply?
cos(a+b)cos(a-b) multiply the expansions for these that you gave me
this is what freckles was talking about (c-d)(c+d)=c^2-d^2
I don't understand, where does c-d,c+d come from and do use distributive to multiply all those terms?
multiply cos(a+b)cos(a-b) by using the expansions you gave me
it would be helpful to memorize (c-d)(c+d)=c^2-d^2 though
you gave me this cos(a+b)=cos(a)cos(b)-sin(a)sin(b) cos(a-b)=cos(a)cos(b)+sin(a)sin(b) all I'm asking you to do right now is multiply (cos(a)cos(b)-sin(a)sin(b))(cos(a)cos(b)+sin(a)sin(b))
this is in the form (c-d)(c+d) which equals c^2-d^2
where c= and d=?
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