A circle has its center at (-1, 2) and a radius of 3 units. What is the equation of the circle?

(x - 1)2 + (y + 2)2 = 3

(x + 1)2 + (y - 2)2 = 3

(x + 1)2 + (y + 2)2 = 9

(x + 1)2 + (y - 2)2 = 9

Question

A circle has its center at (-1, 2) and a radius of 3 units. What is the equation of the circle?

 (x - 1)2 + (y + 2)2 = 3

 (x + 1)2 + (y - 2)2 = 3

 (x + 1)2 + (y + 2)2 = 9

 (x + 1)2 + (y - 2)2 = 9

ipwnbunnies · Answer

General equation of a circle:
$$(x-h)^2 + (y-k)^2 = r^2$$
Where (h,k) is the center of the circle. And 'r' is the radius of the circle.

anonymous · Answer

so are you say B is the correct answer?

ipwnbunnies · Answer

Almost. You got the left side of the equation right. Take a look at the right side again.
r^2 should be on the right side, and the radius of your circle is 3 units.

anonymous · Answer

it would be D right?

ipwnbunnies · Answer

Yes ma'am.