Help!!!! I will fan and give medals!!!! Help!!! Find the zeros of the polynomial function. f(x) = x2 + 9x + 20
I would try to factor it. step 1: list all pairs of numbers that when you multiply them, you get 20 can you do that ?
Get a hint from the plot http://www.wolframalpha.com/input/?i=plot++x%5E2+%2B+9x+%2B+20+from+x+%3D+-6+to++x%3D-3
Notcie that 4+5=9 4(5)=20 Can you factor it now?
i dont understand
Notice that \[ (a+x) (b+x)=x^2 +a x+b x+ a b=x^2+ (a+b)x+ a b \]
Your a=4 and your b=5
\[ x^2+9 x+20=(x+4) (x+5)=0 \] For which valuee your ploynomial is zero?
Can you finish it?
no ive never done this
The zeros are x=-4 and x=-5. If you replace x by -4 or x by -5, your polynomial would be equal to zero
A. 2, 10 B. –4, –5 C. –2, –10 D. 4, 5
\[ (-4)^2 + 9(-4) +20= 16-36 +20=0\\ (-5)^2 + 9(-5) +20=25-45+20=0 \]
so B.
B is your answer
Yes
can you help me with more please
Post it as new problem and tag me in it
ok
Join our real-time social learning platform and learn together with your friends!