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OpenStudy (anonymous):
Help!!!! I will fan and give medals!!!! Help!!!
Find the zeros of the polynomial function.
f(x) = x2 + 9x + 20
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OpenStudy (phi):
I would try to factor it.
step 1:
list all pairs of numbers that when you multiply them, you get 20
can you do that ?
OpenStudy (anonymous):
Notcie that
4+5=9
4(5)=20
Can you factor it now?
OpenStudy (anonymous):
i dont understand
OpenStudy (anonymous):
Notice that
\[
(a+x) (b+x)=x^2 +a x+b x+ a b=x^2+ (a+b)x+ a b
\]
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OpenStudy (anonymous):
Your a=4 and your b=5
OpenStudy (anonymous):
\[
x^2+9 x+20=(x+4) (x+5)=0
\]
For which valuee your ploynomial is zero?
OpenStudy (anonymous):
Can you finish it?
OpenStudy (anonymous):
no ive never done this
OpenStudy (anonymous):
The zeros are x=-4 and x=-5. If you replace x by -4 or x by -5, your polynomial would be equal to zero
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OpenStudy (anonymous):
A.
2, 10
B.
–4, –5
C.
–2, –10
D.
4, 5
OpenStudy (anonymous):
\[
(-4)^2 + 9(-4) +20= 16-36 +20=0\\
(-5)^2 + 9(-5) +20=25-45+20=0
\]
OpenStudy (anonymous):
so B.
OpenStudy (anonymous):
B is your answer
OpenStudy (anonymous):
Yes
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OpenStudy (anonymous):
can you help me with more please
OpenStudy (anonymous):
Post it as new problem and tag me in it
OpenStudy (anonymous):
ok
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