Question

4. A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = –16t² + 60t + 6. What will the height be at t = 3 seconds? (1 point)
35 feet
40 feet
42 feet
45 feet

Answer 1

Just plug in t=3.
\(h(3)=-16(3)^2+60(3)+6\)
The velocity factor is included in the height equation given. I mean, the way the height formula is given to you, it is dependent on on \(t\), the time. So, that's why you just worry about plugging in \(t=3\).

Answer 2

ok, thank you (:

Answer 3

:)