Calculate the discriminant and use it to determine how many real-number roots the equation has.

3x2 – 6x + 1 = 0

A.
one real-number root

B.
three real-number roots

C.
two real-number roots

D.
no real-number roots

Question

Calculate the discriminant and use it to determine how many real-number roots the equation has.

3x2 – 6x + 1 = 0
 
 A.
one real-number root
 
 B.
three real-number roots
 
 C.
two real-number roots
 
 D.
no real-number roots

anonymous · Answer

Compare the given equation with ax^2 + bx + c = 0:

a = 3, b = -6, c = 1

Discriminant, D = b^2 - 4ac = (-6)^2 - 4 (3)(1) = 36 - 12 = 24 > 0

Two real roots.