write an equation in standard form of the line that contains the point (-4,3) and is perpendicular to the line y=4x-1
y = 4x - 1 What is the slope of this line? What will be the slope of a line perpendicular to this line?
what do you mean?
(-4,3)
write an equation in standard form of the line that contains the point (-4,3) and is perpendicular to the line y=4x-1
y = 4x - 1 is the equation of a straight line. Straight line has something called a slope. It represents how steep the angle the straight line makes with the x-axis. So I am asking what is the slope of the line y = 4x - 1?
The first step in solving this problem is to determine the slope of the line y = 4x - 1 and then determine the slope of a line that is perpendicular to y = 4x - 1.
i post the question as i have which is: write an equation in standard form of the line that contains the point (-4,3) and is perpendicular to the line y=4x-1
Yes, I know the question. I am helping you solve the problem by asking you to do the first step. But if you just want the answer then I cannot help you.
ok
the slope is (-4,3)
kll zag
(-4,3) is a point. It is not the slope. In the general equation of a line, y = mx + b, 'm' is the slope and 'b' is the y-intercept. Can you compare y = mx + b to y = 4x - 1 and tell me what the slope 'm' is?
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