Question

the factors of 2y2 - 2y - 4?
The choices are:
(2y - 4)(y - 1)
(2y - 4)(y + 1)
(2y - 2)(y - 2)
(2y - 2)(y + 2)

Answer 1

Plug it in
if it were (2y -4)(y - 1) it'd be 2y2 - 4y -2y + 4 so that'd be 2y2 - 6y + 4. So not number one

Answer 2

Yeah I got that far but then I got off track!

Answer 3

(2y - 4)(y + 1) = 2y2 - 4y + 2y + 4 = 2y2 - 2y - 4
So. what do you think the answer is?

Answer 4

3? I think...

Answer 5

Well Im not sure if you would add or subtract in the second set of ( )

Answer 6

Okay. The 3rd and 4th one cannot be the answer because 2y* 2y = 4y. -4y + 4y = 0 so let's look at the second again?

Answer 7

with (2y - 4) (y + 1) you multiply 2y * y = 2y2

Answer 8

then multiply 2y * 1 = 2y
then -4 * y = -4y
-4 * 1 = -4
so add all of the together and you get 2y2 + 2y - 4y - 4

Answer 9

OK thaank u!!!

Answer 10

simplify that by adding like terms and you get 2y2 = 2y - 4 :)

Answer 11

! Thanks soo much!!!!

Answer 12

Yep :)