I need help ASAP! I will fan and medal anyone who helps me as QUICKLY as possible. 1. Given F(x) = 3x 2 - 4, find F(-√3). 2. Given F(x) = 3x 2 - 4 and F(a) = 8, find a. 3. If F(x) = 2x and G(x) = log x, find F [G(x)]. 4. If F(x) = 3 log x and G(x) = x 2 + 1, find G[F(x)]. 5. If F(x) = log 5 2x, find F -1(x). 6. Which of the following is a rational zero of the function P(x) = 4x 4 + 8x 3 - 7x 2 - 21x - 9? A. -3/2 B. -1 C. -3/4
I'm not sure how to help you past the first one
On the first one is it 3x+2-4 or 3x^2 -4?
it's 3x^2
Yeah, Its raised 2.
Oh okay....
I just have no clue how to do any of this :c
For the first question, plug in -sqrt(3) for x.
\[3(-\sqrt{3})^2 - 4 = ?\]
I got the first one, it was close to five, and that was one of my answers so I chose it haha
Oh, for the second question, set the function equal to 8. 8 = 3x^2 - 4 Can you solve for x?
Err, which ones are we doing then lol.
All of them, besides the first one haha
Alright, do the second one then lol. It's ez peazy.
I am dumbbb. I dont know how to get x because of the squared
Can you do something else first? With the 4?
Add it to the 8 so it is 12=3x^2
Good, then, divide right?
by three and get 4=x^2, the square root and get 2?
Not just 2 buttttt
x=2 ?
When you square root something, you will get the positive of that, like 2. But you can also get the negative of that, -2. (2)^2 = 4 (-2)^2 = 4
The question didn't ask for all values of a, so it's w/e lol
Ohh!!! Okay! That was one of my answers so, next question! :D
f(g(x)) means we're putting the function g(x) into the x's of f(x). :3 Get my drift?
Yes, kinda :P
Let's see if you can do that one then. Show me what you got.
Uhmm, 2logx?
#4 is also the same deal.
Correct :)
okay :D We're on a roll! haha
I think i got the rest of them! Thank you soo much!! you have saved me!!!! <3 <3 <3
Join our real-time social learning platform and learn together with your friends!