how do I simplify a^2b^3 over ab^2c
can anybody help me please !!!
\(\ \sf \Large \dfrac{a^2b^3}{ab^2c} \) ?
yes
ab/c
\(\ \sf \dfrac{a^2}{a} = a^{2-1} = a^1 = a \) \(\ \sf \Large a = a^1 \) Same thing xD So subtract the exponents, What is \(\ \sf \dfrac{b^3}{b^2} = b^? \) I already did \(\ a \) for you :)
b^1 right
okay is it okay that I ask yhu nore questions like will yhu help me on them
When you divide you subtract the exponents, when you multiply you add them! Yes! \(\ \sf \dfrac{b^3}{b^2} = b^{3-2} = b^1 = b \) ! so you have \(\ \sf ab \) so far Now, there's nothing to divide C with so you're simply left with \(\ \sf \Large \dfrac{ab}{c} \)
Sure, ask :)
simplify (-3m^5)
Are you sure it's not \(\ (-3m)^5 \) ? Otherwise that would just be \(\ -3m^5\), you can't do anything with that <--
okay factor 5x^2+5x-30
But wait, which is it, -3m^5 or (-3m)^5 ?
okay I got x^3-6 is that right
(-3m^5)
Um, my internet got disconnected -_- Anyways, 5x^2+5x-30 5(x^2 + x - 6) x^2 + 3x - 2x - 6 x(x + 3) -2(x + 3) 5(x+3)(x-2)
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