Question

Simplify: ( y^−7 × y−^3 )^−1

Answer 1

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When anything is to the negative first power, we just switch the signs on the inside of the parenthesis.

\[ ( y^{−7} × y^{-3} )^−1 = (y^{7} \times y^{3})\]
Now we see we have two exponents that need to be multiplied together. This simply means ...When you are multiplying, and the bases are the same, you ADD the exponents.\[y^{7 + 3} = ?\]