Question

Solve the system of equations:
(4/x)-(3/y)=0
(6/x)+(3/2y)=2

Answer 1

Start by eliminating the fractions.

Answer 2

i think for this one i would just do a straight substitution
solve first equation for x

4/x = 3/y ---> x/4 = y/3 ---> x = 4y/3

plug into 2nd equation
6/(4y/3) + 3/2y = 2

18/4y + 3/2y = 2

multiply everything by "y"

18/4 + 3/2 = 2y

y = 3