can someone help me

2. Where is the vertex of the parabola?

y = x2 + 2x – 3

Above the x-axis
Below the x-axis
On the x-axis
On the y-axis

3. Use the discriminant to determine how many x-intercepts the graph of the equation has.

y = – 4x2 + 4x – 1

zero
one
two
three

4. In which direction does the parabola open?

y = 3x2 – 5x – 10

down
right
left
up

5. What are the x-intercepts of the quadratic function?

y = x2 + x

2 and 1
–2 and 1
2 and –1

Question

can someone help me

 2. Where is the vertex of the parabola?

y = x2 + 2x – 3

       Above the x-axis
       Below the x-axis
       On the x-axis
       On the y-axis

 3. Use the discriminant to determine how many x-intercepts the graph of the equation has.

y = – 4x2 + 4x – 1


       zero
       one
       two
       three

 4. In which direction does the parabola open?

y = 3x2 – 5x – 10


       down
       right
       left
       up

 5. What are the x-intercepts of the quadratic function?

y = x2 + x 

  2 and 1   
     –2 and 1  
      2 and –1

anonymous · Answer

the first coordinate of the vertex of $y=ax^2+bx+c$ is always $-\frac{b}{2a}$ 
for $y = x^2 + 2x – 3$ you have $a=1,b=2$ so the first coordinate is $-\frac{3}{2}$

anonymous · Answer

to find the second coordinate of the vertex, replace $x$ by $-\frac{3}{2}$ and see what you get
it if is a positive number, then it lies above the $x$ axis, and if it is a negative number then it lies below the $x$ axis