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An observer on the ground is x meters from the base of the launch pad of a rocket, which is at the same level as the observer. A few seconds after the rocket takes off vertically, the observer sees its tip at an angle of q° from the horizontal. How far above the ground is the tip of the rocket at that instant? Assume that the ground is level.
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Here's a sketch of the situation. How would you start? |dw:1397600517259:dw|
i would start by deciding whether to use sin cos or tan?
i kinda confused but i believe it would be x tan over q ?
\[tan(q)=\frac{h}{x}\] so\[h=x tan (q)\]
so the one i picked was right ?
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