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Solve: |2x - 7| < 13 A. x < 10 B. x > 10 and x < -3 C. -3 < x < 10 D. x > -3
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In general if you have an inequality of the form |ax + b| < c Then it is equivalent to -c < ax + b < c which is equivalent to -c - b < ax < c - b which is equivalent to -(c + b)/a < x < (c - b)/a
thank u so much! :)
yw
Actually, let me make one last correction: For example, if you have |3x + 9| < 12, then it is equivalent to -12 < 3x + 9 < 12 which is equivalent to -12 - 9 < 3x < 12 - 9 which is equivalent to -21 < 3x < 12 - 9 which is equvalent to -21/3 < x < 3/3 so -7 < x < 1 is the solution
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