Solve (for x).
-2(x+2)^2 + (x-1)^2 = 0
This is how far I got:
-2(x^2 + 2x + 2x + 4) + (x^2 - x - x + 1) = 0
-2(x^2 + 4x + 4) + x^2 -2x + 1 =0
-2x^2 - 8x - 8 + x^2 - 2x + 1 = 0
-x^2 - 10x - 7 = 0
Am I on the right track? If so, what do I do next?

Question

tkhunny · Answer

x+20 or x+2?  That's quite a bit different.

anonymous · Answer

x+2 sorry!  :)

anonymous · Answer

you can and might have to use quadratic formula

anonymous · Answer

$$x= \frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }$$ ?

anonymous · Answer

yup 

to make it easier Just multiply both sides by negative one 

so 
-x^2 - 10x - 7 = 0
or x^2 -10x -7=0
ax+bx+c=0

a=1
b=10
c-7

plug in your done

anonymous · Answer

Thank you very much! :D

anonymous · Answer

np