Write an equation in point-slope form of the line through point J(4, –4) with slope 4.
\[Y-Y1 = m(X-X1)\]
That's point-slope form, where (X1.Y1) is the given point.
so y-4=4x+4 ?
Err no try again. Also, 'm' is the slope of the line. Also don't forget youur Y value is actually negative.
or y+4=4x-4
Eh, almost. You got the left part right. This is what the right should look like: 4(x-4) You have to distribute the 4 to each component.
-4(x-4) ?
Err, no lol. We're keeping 4(x-4) But you have to distribute the 4 to each term. 4(x-4) = 4*x - 4*4 = 4x - 16. y + 4 = 4x - 16
well that's not any of my choices
Ehh, what are your choices? o.o
You have to reduce it to slope-intercept form, perhaps? Which means getting y by itself?
a. y+4=4(x+4) b. y+4=4(x-4) c. y-4=4(x+4) d. y+4=-4(x-4)
Oh yeah, it's B. y + 4 = 4(x-4)
Das what I showed you. :3
@Jack1
Um...ok.
i'm stuck between b and c can you help
that was for jack btw
I said it was B! Point (4,-4) , slope of 4 (y-y1) = m(x-x1) (y+4) = 4(x-4)
hey shay, bun's helpin u out here, bear with him
but you were confusing me taking me all around the world at first
Sorry. I was just showing you how to do it.
when i asked if that was the correct answer way before but okay thanks for your time guys :) much appreciated
Ohhh, you didn't put parentheses around your original answer. That's why :o
ok
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