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OpenStudy (anonymous):
find an equation of the line containing the given pair of points.
(4,2) (12,7)
y=
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OpenStudy (anonymous):
first you need to find the gradient between the two points. can you find it?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
its (y1-y2)/(x2-x1)
OpenStudy (anonymous):
try that
OpenStudy (anonymous):
when you get the gradient,m
you just pick one of the point and plug in the value in this equation:
y-y1 = m(x-x1)
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OpenStudy (anonymous):
i honestly dont get it
OpenStudy (anonymous):
do you know how to do the problem ?
OpenStudy (anonymous):
ok, to find the gradient(m), its (y1-y2)/(x1-x2),
so m = (2-7)/(4-12)
OpenStudy (anonymous):
ok so how owuld you solve it for the equation
OpenStudy (anonymous):
when you get the m which is 5/8,
you substitute it in the equation y-y1 = m(x-x1)
youll get y-2 = (5/8)(x-7)
then solve for y.
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OpenStudy (anonymous):
how owuld you solve fory if y isnt by the equal sign?
OpenStudy (anonymous):
i mean just bring the -2 to right hand side, or you can just leave it there.
but it would be nicer if the equation be in form of y = mx +c
OpenStudy (anonymous):
so y=mx-2
OpenStudy (anonymous):
i mean from this equation y-2 = (5/8)(x-7)
ypull get y = (5/8)(x-7)+2
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