Question

Solve the system of equations.

x + 3y = -1
2x + 2y = 6

(-4, 1)

(2, -1)

(4, -1)

(5, -2)

Answer 1

Given the following system of eqn, you could either use the substitution or elimination method

\(\begin{align}x + 3y &= -1 \\2x+2y &= 6\end{align}\)

Let's go in favour of the first

We get an expression with respect to \(x\)

\(x = -3y - 1\)

Substiture value of \(x\) into the second given eqn and solve for \(y\)

Answer 2

add 3 to each side , right?

Answer 3

Nope, I meant where you see \(x\) put \(-3y-1\) right there

Answer 4

so -3y-1

Answer 5

Like this\(\ldots ~2(-3y-1) +2y = 6\)

Answer 6

Expand that and solve for \(y\). Can you attempt that?

Answer 7

now i do the 2 sides?

Answer 8

Show me what you mean.

Answer 9

+3y +1

Answer 10

i got x=-3/4

Answer 11

That's incorrect \(\bigotimes\)

Answer 12

D

Answer 13

5,-2

Answer 14

You're only guessing. :(

Answer 15

i just got y=-2 from doing the equation

Answer 16

Expanding this: \(2(-3y-1) +2y = 6\) gives

\(-6y-2 +2y=6 \longrightarrow -4y = 8 \longrightarrow y=-2\)

Substitute \(y= -2\) in \(x + 3y = -1\), you'll get

\(x + 3(-2) = -1 \longrightarrow x - 6 = -1 \longrightarrow x = 5\)

So, you get your guessed answer,

\(\left(5, -2\right)\)

Answer 17

It wasnt guessed.

Answer 18

"i just got y=-2 from doing the equation" ??? \(\longleftarrow\) I don't think so, simply because you couldn't show your work. But it's okay