Solve the following system of equations: x - 2y = 14 x + 3y = 9 (1, 12) (-1, -12) (12, -1) (12, 1)
do you prefer substitution or elimination ?
elimination
C
Can you work step by step with me? so i can fully understand?
(12,-1)
x - 2y = 14 x + 3y = 9 --->(-1) -------------------- x - 2y = 14 -x - 3y = -9 (result of multiplying by -1) --------------------add -5y = 5 y = -1 now sub -1 in for y in either equation to find x x - 2y = 14 x - 2(-1) = 14 x + 2 = 14 x = 14 - 2 x = 12 answer is : (12,-1) --- sheelo_mughal is correct
I cant, i just do everything in my head
why wasnt the 2 added to the 14? thats where i messed up.
because when a number goes across the equal sign, it changes its sign....thus, making the 2 become -2
x+2=14 so when to passes = its sign will automatically change to - x=14-2 x=12
Okay i didnt want the answer but thank you, the mistake i made was not changing the sign. I kept it the same.
Just remember the rules of solving equation.
Thanks. I asked for them to help. If you read what i just said you would know the facts.
Thanks, when eliminating with 2 variables do i just keep it the same?
no if u want to move a variable across the = then its sign must change
+ will become - - will become + X will become\[\div \] \[\div\] will become X
Thanks can i show you 1 more i just did and can you check to see if what i have is right?
ya ofcourse
If you were solving a system of equations and you came to a statement like 1 = 3, what do you know about the solution to the system? The solution is (1, 3) The solution is x = 1 and y = 3 There is no solution There are infinitely many solutions I got C. (No solution)
is it 1=3 or (1,3)
just 1=3
if its y=3 then u can say its B but if its 1=3 then C is right
Thank you
ur welcome
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