Question

Use the discriminant to describe the roots of each equation. Then select the best description.
Please Help!
16x^2 + 8x + 1 = 0

Answer 1

let "d" be the discriminant
d=8^2-4*16=0
so the equation has double root x=(-8)/(2*16)=-8/32=-1/4
so 16x^2+8x+1=16(x+1/4)^2=0 i.e. x=-1/4

Answer 2

I still don't get it.. can you explain it to me again?

Answer 3

to calculate the discriminant "d" of an equation ax^2+bx+c=0
d=b^2-4*a*c
in our case a=16,b=8 and c=1
so d=8^2-4*16=64-64=0
is it clear till now ?

Answer 4

Okey, I'm starting to understand it now, thanks.