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Factor the expression. k2 – 9h2
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bionmial \[(a+b)(a-b) = a^2 - b^2\]
I don't get it do we plug them in
formula is actually called difference of squares, and you can also have numbers example: \[(a+4b)(a-4b) = a^2 -4ab +4ab -16b^2\]
this uses FOIL, and -4ab +4ab cancel out
can you try the same with the one in the problem? \[k^2 - 9 h^2\]
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\[(a+4b)(a-4b) = a^2 -16b^2\] similar: \[(k+..)(k-..) = k^2 -9h^2\]
how do I do this again I am confused
The original equation looks like this \[k^2 - 9 h^2\]
so it looks like a difference of squares
yes
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the formula for factoring a difference of squares: \[(a+b)(a-b) = a^2 - b^2\]
what do I plug in for a and b
k and h
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