Keisha is solving the equation 7^x = 9. Which shows the first step she should take? log 7^x = 9 7^x = log 9 log 7^x = ln 9 log 7^x = log 9
First one.
How do you know? Show me how you would work it out
@hartnn @whpalmer4 Can you guys help me?
Okay, hold on.
take the log of both sides of the equation
and make sure its the same base log.... so D
Log should be placed first because it's conversion . 7^x = 9 This cannot be simplified without log log 7^x = 9....
the 1st line is \[\log(7^x) = \log(9)\] next apply the log law for powers \[x \times \log(7) = \log(9)\] now you can solve for x
log 7^9 = x log 7/ log 9 = 1.9459101490553132/2.1972245773362196 = 0.8856218745807111 = 0.89
@campbell_st The bases are NOT the same so it cannot be solved that way. 7 = 9 is not true so DO NOT put log on both sides.
well here is a simple idea... looking at the solution @YISODUMB15 has posted... test his solution given his answer of 0.89 does \[7^{0.89} = 9\] use a calculator to check
No need for a calculator — raising 7 to a power < 1 isn't going to give you a number > 7!
However, solving as @campbell_st suggests does give you the right answer...
Oops
Posted it again lol
@whpalmer4 Exactly, Someone with sense. I solved it incorrectly but it isn't asking for a solution.
@campbell_st has plenty of sense, and is adding some value by showing how you would continue on to the solution.
its asking for the 1st line of the solution... so you can get the correct solution
The way he or she said it would be correct if it was 7^x = 7. However the bases are 7 and 9 which are not the same number. Also, I know @campbell_st has sense, her method is very useful, it just shouldn't be implied in this question.
the question is asking.... 7 to what power is equal to 9... 7 is the base, x is the power or exponent and 9 is the basic numeral...
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