The length of a rectangle is 3 times its width. If the length were increased by 2 inches and the width by 1 inch, the new perimeter would be 62 inches. What is the width and length of the rectangle?

If w represents the width of the rectangle, then which equation could be used to solve for w?
A.(w + 1)(3w + 2)=62
B.2(4w + 3) = 62
C.2(3w + 3) = 62

Question

The length of a rectangle is 3 times its width. If the length were increased by 2 inches and the width by 1 inch, the new perimeter would be 62 inches. What is the width and length of the rectangle?

If w represents the width of the rectangle, then which equation could be used to solve for w?
A.(w + 1)(3w + 2)=62
B.2(4w + 3) = 62
C.2(3w + 3) = 62

campbell_st · Answer

well let the width be w

then the length is 3w

add 2 to the length so   l = 3w + 2

add 1 to the width so    w = w + 1

now perimeter is   P = 2w + 2l 

so substituting the known information 

62 = 2(w + 1) + 2(3w +2)

campbell_st · Answer

or using 

P = 2(l + w)

62 = 2(3w + 2 + w + 1)

this maybe easier to simplify