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- tan2x + sec2x = 1
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@Luigi0210
There is an identity, tan²x+1=sec²x tan²x+1=sec²x subtract tan²x from both sides, and you will get... 1=sec²x-tan²x See? it is in fact equal to 1.
start with \[\sin^2 + \cos^2 = 1\] divide every term by cos^2.... then rewrite it with the trig ratios on the same side of the equation
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