Solve for x? √ (5x-1) = √ (4x+9)
square both sides (just like before) .
do i have to do it separately? since there are 2.
Well, if you had √(x+1) = √(2x-2) after squaring both sides, the square roots would just disappear, and you would get x+1=2x-2 then.. 1=x-2 x=3 So, what happens if you square both sides, in YOUR problem ?
I have no idea. I'm confused because there are 2.
raise each side to the second power.... lets start with the left side √ (5x-1) = √ (5x-1) ² (raised to 2nd power) = 5x-1. now continue with the right side √ (4x+9) = √ (4x+9) ² (raised to 2nd power) = 4x+9. So, after raising BOTH SIDES to the SECOND POWER, you would get 5x-1=4x+9 See? Can you take it from here ?
do you just subtract?
After squaring both sides? Yes... 1) subtract 4x from both sides 2) add 1 to both sides. The answer is ?
5-4 is 1 and 4-4 is 0. do you put those together to get 10?
I don't really get what you said by 4-4 =0, but yeah, the ans. is 10 .
well how do you understand it then?
I don't want to do something wrong and mess up on the others
5x-1=4x+9 -4x -4x x-1=9 +1 +1 x=10
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