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Simplify.
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@Xmoses1
x^2 will cancel. Cross both x^2 (on top and bottom) . 4 and 20... you are canceling fours, instead of 4 you get 1, and instead of 20 you get 5. Since there is a minus next to the first fraction, your answer would be negative.
Oh, sorry....
\(\Huge\color{blue}{ \bf (-\frac{x}{4})^{2} \times \frac{20}{3x^3} }\) \(\Huge\color{blue}{ \bf (\frac{x^{2} }{16}) \times \frac{20}{3x^3} }\) \(\Huge\color{blue}{ \bf \frac{20x^{2} }{48x^{3} } }\) \(\Huge\color{blue}{ \bf \frac{5 }{12x } }\)
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I was literally blind, sorry for the err... again.
thank you!
You welcome ! (good that I noticed the err :) )
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