Question

Simplify and identify the domain.

Answer 1

@Xmoses1

Answer 2

\(\LARGE\color{black}{ \bf \frac{-6}{6x+24} \times \frac{3(x+2)}{x^2-4}}\)


\(\LARGE\color{black}{ \bf \frac{-6}{-6(-x-8)} \times \frac{3(x+2)}{(x+2)(x-2)}}\)


\(\LARGE\color{black}{ \bf \frac{1}{1(-x-8)} \times \frac{3(x+2)}{(x+2)(x-2)}}\)

more coming......

Answer 3

\(\LARGE\color{black}{ \bf \frac{3(x+2)}{(x+2)(x-2)(-x-8)}}\)


\(\LARGE\color{black}{ \bf \frac{3}{(x-2)(-x-8)}}\)

Answer 4

You know that the denominator can't be equal to zero, so...

(x-2)(-x-8)=0
x-2=0
x=2

-x-8=0
-x=8
x=-8

Thus you know that

x≠ -8 and x≠2 but all other real numbers besides -8 and 2 can be the domain.

Answer 5

Shi t.. err again !

Answer 6

Where I said -x-8 , it should be -x-4....

So,

(x-2)(-x-4)=0
x-2=0
x=2

-x-4=0
-x=4
x=-4

x≠ -4 and x≠2 but all other real numbers besides -4 and 2 can be the domain.

Answer 7

Also, positive 2 is one of the values that are excluded from the domain...

Answer 8

I said it, .. neg. is also excluded.

I am stupid, sorry :)

Answer 9

you are not stupid

Answer 10

Hopefully

Answer 11

and thank you!