area of composed figures
number 1, it is made up of a trapezoid and a triangle area of trapezoid = (1/2)(base1 + base2)(height) = (1/2) (2+ (2+2+2)) (4) = ? area of triangle = (1/2)(base)(height) = (1/2)(2+2+2)(3) = ? then add them together to get the area of the pentagon :)
yeh i got 25
for number 2 do you count the half squares
the middle part of that figure would be a parallelogram with base of 1 and height of 2 area of parallelogram = base times height
i got 16 by 8 times 2 8 being 4 on bot sides
oh i see how you get 10, 8 pus 2
yep :)
how do u solve 3 though
http://prntscr.com/3ayzhk you have a trapezoid and a rectangle area of trapezoid = (1/2)(base1+base2)(height) = (1/2) ( 5 + 15 ) (7.5) = ? area of rectangle = (base) (height) = (15) (7.5) = ? then add them together
ok so 187.5 and number 4
number 4 is a little more complicated :) first understand that divided into 3 equal parts gives you http://prntscr.com/3az223
ok
Which can give you 3 overall areas two of which would be triangles http://prntscr.com/3az3bp you can then find the areas of the triangles and subtract it from the overall area of the rectangle
ok
so rectangle (total) area = 2 times 3 = ? left triangle = (1/2)(2)(2) = ? right triangle = (1/2)(3)(4/3) = ? total minus (triangle + triangle) = ? that last ? divided by total = answer
wht do u mean total minus triangle plus triangle
the three question marks before that... rectangle - triangle - triangle = ? when rectangle (total) area = 2 times 3 = ? left triangle = (1/2)(2)(2) = ? right triangle = (1/2)(3)(4/3) = ?
so 6 - 2- 1.9 or 2
yep :) then 2 divided by 6 = (simplify) = answer
oh ok
so 0.333 of the flag is painted red
i could write that as a fraction of 2/6
or 1/3 :P
k thanks
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