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What is the equation of a line passing through the point (a, b) and having a slope of b?
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The point-slope form of a line with a slope of m that passes through the point \[(x_o,y_o)\] is: \[y-y_o = m(x-x_o)\]
I have y=-bx-b(1-a) y=bx-b(a-1) y=1/bx+b(a-1) y=-1/bx+b(1-a) :/ I dont know how to get it in the right form, it doesnt look like any point slope i have ever seen
I cant see how they got any of those 4 options, i have no IDEA which one is correct
If we plug in what we know, we'll get: \[y - b = b(x - a)\] \[y -b = bx-ab\] \[y=bx-ab+b = bx+b(1-a)\]
Which is equivalent to: \[y=bx-b(a-1)\]
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oh! thank you! you rock!!! i have like 5 questions using this!
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