Question

how do you solve y=x^2-11x+24 y=x-3 Solve each system

Answer 1

Alright. Let's plug in x-3 where you see y.
What would your equation look like?

Answer 2

x-3=1x^2-11x+24?

Answer 3

Great :D
Now, let's get everything on one side and have zero on the other side. What do you have then?

Answer 4

0=1x^2-10x+27?

Answer 5

-12x instead of -10x, since you're subtracting x from both sides :)

Answer 6

oooh

Answer 7

So you have x^2-10x+27. Now, can you factor this?

Answer 8

you mean -12?

Answer 9

-12, my bad XD

Answer 10

lol

Answer 11

LOL xD

Answer 12

Let's try that again:
See if you can factor x^2-12x+27 :)

Answer 13

-9&-3

Answer 14

(x-3)(x-9) :3
So x would be 3 and 9..

Answer 15

the answer should be 3,0 and 9,6 though

Answer 16

It will be, when you finish the problem and solve for y.

Answer 17

Oh, yup XD

Answer 18

hooow?

Answer 19

You have solved for x.
The problem states y = x - 3
Substitute your x values and solve for the two y values.

Answer 20

oh its that easy?

Answer 21

uh i got -12 so thats not right

Answer 22

Yes. y = 9 -3 = 6 (9,6)
y = 3 - 3 = 0 (3,0)

Answer 23

i got -9 & -3

Answer 24

(x-9)(x-3)= 0 solve getting x=9 and 3

Answer 25

ok ok...how do you do y=2x^2+x+4 y=-x^2-x+9