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Mathematics 10 Online
OpenStudy (anonymous):

If f:A->B and g: B->A. Is this enough to say f and g are onto?

OpenStudy (anonymous):

Well it could be that \(\forall x\quad f(x) = b\in B\) and \(\forall x\quad g(x) =a\in A\). they'd both be constants and not onto.

OpenStudy (anonymous):

|dw:1397792011372:dw|

OpenStudy (anonymous):

wait.. hold on

OpenStudy (anonymous):

oh I see it now,

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