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MIT 18.01 Single Variable Calculus (OCW) 14 Online
OpenStudy (anonymous):

0=ln(x)/2

OpenStudy (anonymous):

0=ln(x)/2 multiplying both side by 2 we get 0 = ln(x). But we know that ln(1) = 0 so compairing we get ln(x) = ln(1) this gives you x = 1 I hope this will help you :)

OpenStudy (anonymous):

Or take: \[e ^{0}=e ^{\ln x}\] --> 1=x

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