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MIT 18.01 Single Variable Calculus (OCW)
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0=ln(x)/2
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0=ln(x)/2 multiplying both side by 2 we get 0 = ln(x). But we know that ln(1) = 0 so compairing we get ln(x) = ln(1) this gives you x = 1 I hope this will help you :)
Or take: \[e ^{0}=e ^{\ln x}\] --> 1=x
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