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Mathematics 17 Online
OpenStudy (anonymous):

If (x+5)^2=35, what is the approximate potive value of x?? Answers A.0.92 B.2.65 C.3.16 D.5.48

OpenStudy (anonymous):

Can somebody help me??

OpenStudy (mathmale):

You have x embedded in an equation, a quadratic equation. You're being asked to SOLVE this equation for x (the positive value of x only).

OpenStudy (anonymous):

So the answer is A 0.92??

OpenStudy (mathmale):

If:\[ (x+5)^2=35\] the first thing we do is to take the square root of both sides. Why? Because this will remove the exponent, 2. Please show how you got your answer.

OpenStudy (mathmale):

@pbrianna100? I'd appreciate receiving an answer. Thank you.

OpenStudy (anonymous):

um okay??

OpenStudy (mathmale):

Your suggested answer, 0.92, is correct. I emphasize understanding over "answers," which is why I asked you to explain how you got your answer. Please do that next time, OK? Welcome to OpenStudy!! Hope you find it very profitable to interact with other students here.

OpenStudy (anonymous):

@mathmale okay, will do.

OpenStudy (anonymous):

Need help.!!!! A quadratic equation x^2-14x+41=0 Which of the following is the first correct step to write the above equation in the form (x-p)^2=q where p and q are integers?? Answers. A. Add 8 to both sides of the equation B. Add 9 to both sides of the equation C. Subtract 8 from both sides of the equation D. Subtract 9 from both sides of the equation

OpenStudy (anonymous):

Can somebody help me with this question please anybody!!!

OpenStudy (anonymous):

@crabby_patty

OpenStudy (anonymous):

A ball is thrown upward from the top of a building. The function below shows the height of the ball above the ground, F (t) in feet, at different times (t) in seconds. F (t)=-16T + 34T +80. The average rate of change of F (x) from x=5 to x=7 is... @RockStar02

OpenStudy (anonymous):

How is time negative?

OpenStudy (anonymous):

@RockStar02 T isn't negative

OpenStudy (anonymous):

-16T?

OpenStudy (anonymous):

@RockStar02 -16t^2

OpenStudy (anonymous):

@RockStar02 I guess you don't get it??

OpenStudy (anonymous):

oh nevermind

OpenStudy (anonymous):

What are the answer choices

OpenStudy (anonymous):

@RockStar02 There no answer choices for this one

OpenStudy (anonymous):

Well if I did it right, then it's 1492. But idt thats right

OpenStudy (anonymous):

It's not right, nevermind. What grade is this?

OpenStudy (anonymous):

What math lesson too? Like what is this?

OpenStudy (anonymous):

@RockStar02 You don't know if is right.?? I will skip that one you think you can help me with another one if I post it on here??

OpenStudy (anonymous):

Post it on a new thing. I don't think it's right. I did 16^2+34^2+80 I don't know what the last part with the x's are about. I didn't see any other x variables in the question. @mathmale

OpenStudy (anonymous):

@RockStar02 I will just skip this one and come back to it.

OpenStudy (anonymous):

Close this question, and post a new one. You can't keep reusing the same question.

OpenStudy (anonymous):

@RockStar02 Okay, I am going to post a new question right now.

OpenStudy (anonymous):

A company launched four new products. The market price, in dollars, of the four products after different number of years is shown below: Table displaying data. The first column one shows the heading number of years, and rows product 1, product 2, product 3, product 4. The next column heading says 1 with rows 2.00, 2.20, 2.20, and 2.80. The next column header says 2 with rows 4.00, 4.80, 6.40 and 3.20. The next column header says 3 with rows 8.00, 6.80, 11.60, 3.20. The last colunn heading says 4 with rows 16.00, 9.20, 18.80 and 2.80. The price of which product will eventually exceed all others? Product 1 Product 2 Product 3 Product 4

OpenStudy (anonymous):

@RockStar02

OpenStudy (anonymous):

I TOLD YOU TO MAKE A NEW QUESTION

OpenStudy (anonymous):

Stop using the same question to post new questions in the comments! Close the question, and post a new one!

OpenStudy (anonymous):

@RockStar02 I did. I just posted it

OpenStudy (anonymous):

NO. AND STOP TAGGING ME, YOU DO IT ONCE I WILL BE TAGGED You did not, you have to CLOSE THE QUESTION! See the button that says CLOSE???? Click it! Then, paste the question that you have in the "Ask a question..." thingy! Not in the chat box!

OpenStudy (anonymous):

I'm sorry for being rude, but I've had a rough day and I'm typing retarded today so I have to keep retyping things

OpenStudy (anonymous):

@RockStar02 It's okay. I get it, I will post my next question where it says ask a question.

OpenStudy (anonymous):

-_- Stop. Tagging. Me. In. The. Same. Question.

OpenStudy (anonymous):

Close. This. Question.

OpenStudy (anonymous):

good. Now. Post. The. New. One.

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