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You have five $1 bills, four $5 bills, six $10 bills, and three $20 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill. What is P($1, then $10)?
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1/1
sorry 1 $ is 1/18 and 10$ is 1/3
@johnz
am i right
what is the probability of just picking a $1 bill?
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5/18
I'm asking neonstormtrooper, akshay247
5/18 * 6/17 = 5/51
All I had to do was multiply the fractions?
yes
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Thanks to all of you (:
do you see how johnz got that answer?
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