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Chemistry 19 Online
OpenStudy (anonymous):

Fellas, can somebody be kind and share a question and solution regarding substitution and elimination/RADICAL REACTION? I study hard and just wanna see that i am capable of solving it. Thanks!

OpenStudy (anonymous):

@abb0t please don't let me down!

OpenStudy (abb0t):

What's the question?

OpenStudy (anonymous):

I am asking if you have an example for a question regarding radical reacion/substitution and elimination.... It's very theoretical but I have no idea if I fully understand this. Do you have one by any chance?

OpenStudy (abb0t):

I can think of one.

OpenStudy (anonymous):

Thank you! You areunambiguously the organic chemistry master!!!!

OpenStudy (abb0t):

Hmm...well, ok. Hold on. Let me start off with a fairly easy one

OpenStudy (abb0t):

|dw:1397933442070:dw|

OpenStudy (abb0t):

Do you want to try it yourself first or just want an explanation?

OpenStudy (abb0t):

Show the detailed mechanism.

OpenStudy (abb0t):

by the way, \(\Delta\) means i added heat.

OpenStudy (anonymous):

wow did you just make it?

OpenStudy (anonymous):

hmmm... let's see, so we start with initiation, meaning we have homolytic breaking of bonds eh?

OpenStudy (abb0t):

yes. There are 3 major parts: \(\sf \color{red}{initiation},~\color{blue}{propagation}, ~and~\sf \color{green}{termination}\)

OpenStudy (anonymous):

later we have propagation and we get methylbromine cyclohexane?

OpenStudy (anonymous):

I think I got confused a little bit, can you help me out?

OpenStudy (abb0t):

|dw:1397933884259:dw|

OpenStudy (anonymous):

that's the Initiation step am I right?

OpenStudy (abb0t):

breaking of the homolytic bond. make sure that you use half-arrow notation. it's important. and yes, this is initiation step.

OpenStudy (anonymous):

Really? is it that important?

OpenStudy (abb0t):

YES. It's very important that you know your curved arrow notation. |dw:1397933987998:dw|

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