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Solve the following quadratic-linear system of equations.
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\[y=x ^{2}-8x+19\]
\[y=2x-6\]
substitute equation 2 in equation 1 to solve for the variable "x" it will be \(2x-6=x^2-8x+19\), simplify it and solve for x using quadratic formula and then once you find the values of x, substitute these to find the value(s) for "y"
making it (4, –6) and (2, 5)? @Data_LG2
give me a sec, i'll solve it
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ok
for "x" i only got one value , x=5 because the equation will end up like this \(x^2-10x+25=(x-5)^2\) so y will be \(y=2(5)-6=4\) therefore it will be (5,4)
Thankyou so much!
np;)
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