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That drawing isn't so good. Do I have the 250 feet and the 265 feet distances drawn in correctly?
@mamatodylan : Can we say that the 2 blue lines in the attached diagram are parallel?
@mamatodylan : Alright, so we can resolve this land plot into 2 trapeziums. Area of 1st trapezium = 0.5x(265+125)x(260-150) ft^2 = 21450 ft^2 Area of 2nd trapezium = 0.5x(265+150)x150 ft^2 = 31125 ft^2 Total area of the plot = 21450+31125 ft^2 = 52575 ft^2 Hence, Mr. Jones will be able to get this land. To answer the problem as is required, 1. Restatement of the problem: Mr. Jones will only be able to get the land plot if it has an area of at least 42060 ft^2. 2. Find the minimum area of the land plot which is required for the quoted price; if the actual land area exceeds this minimum value, Mrs. Smith will buy the plot for Mr. Jones (as it is priced at a lower rate than $4/ft^2). 3. The rate at which the plot is being sold is $3.20/ft^2 (lower than the value of $4/ft^2 quoted by Mrs. Smith to Mr. Jones), hence Mr. Jones will be able to get the plot. 4. It is evident here that Mr. Jones will be able to get the plot as it is being retailed at a lower rate than what Mrs. Smith had originally quoted to Mr. Jones ($4/ft^2).
@shiraz how did you get this figure of $3.20? The rate at which the plot is being sold is $3.20/ft^2 (lower than the value of $4/ft^2 quoted by Mrs. Smith to Mr. Jones), hence Mr. Jones will be able to get the plot.
@shiraz14 how did you get this figure of $3.20? The rate at which the plot is being sold is $3.20/ft^2 (lower than the value of $4/ft^2 quoted by Mrs. Smith to Mr. Jones), hence Mr. Jones will be able to get the plot.
@mamatodylan: Sorry for the delayed reply - just saw this now. The price per square foot is the total cost divided by the area of the land - the total cost of the land was $168240 and the total land area was 52575 ft^2, hence the cost psf is $3.20.
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