1.) Line k has x-intercept of ? 2.) Line k has y-intercept of ? 3.)The slope of line k is ? 4.) Write the equation of line k in slope-intercept form (y=mx + b). 5.) Write the equation of line k in standard form (Ax + By = C).
1.) Line k has x-intercept of ? Where does line k cross the x-axis? 2.) Line k has y-intercept of ? Where does line k cross the y-axis? 3.)The slope of line k is ? slope is rise/run so how many up or down/how many left or right, slope will be negative 4.) Write the equation of line k in slope-intercept form (y=mx + b). where m=slope and b=y-intercept 5.) Write the equation of line k in standard form (Ax + By = C). Can be solved after you have #4 and can explain. Tell me what you get for these and I will help you. I will tell you if you are correct.
X intercept = 6 y intercept = 4 how would i find slope with that?
That is correct rise/run=y/x so in your case y=4 and x=6 so 4/6= 2/3 And it's going to be negative be it is going down to the right. So slope = -2/3
So what is slope-intercept form (y=mx+b) of line k?
y=-2/3+4
Yupp. Do you know how put that in Standard form(Ax+By=C)? Or do you need help with that?
i think i forgot to put x in
Yes you did, but you get what your doing. x goes right after the 3
so would it be y=-2/3x+4?
yes
but you need standard form ?
ok :) yes i also need help with standard form
y = -2/3x + 4 -- add 2/3x to both sides 2/3x + y = 4 -- you cannot have fractions, so multiply entire equation by 3 2x + 3y = 12 -- standard form any questions ?
so multipy 2/3, y and 4 by 3?
but how do i know how much to multiply by, in this case 3?
you multiply by the LCD of all the numbers...in this case it is 3.
When doing standard form Your A always has to be positive In yours case this isn't a problem since x is negative I like to start by first getting rid of the fractions. To get rid of fractions you multiply the fraction by it's reciprocal. the opposite of a number/3 is 3. So really you just multiply by the number on the bottom to cancel eachother out. But make sure you multiply everything by 3. So you do y*3 -2/3 * 3 and 4*3 You get 3y=-2x+12 Now you want -2x on the other side so you want to add both sides by 2x the 2x on the right will cancel out you also want the x to be in front of the y (hence Ax+By=C) So your final answer is 2x+3y=12
2/3x + y = 4 -- let me add this step, it might make it clearer... 3(2/3)x + 3(y) = 3(4) 6/3x + 3y = 12 2x + 3y = 12 understand ?
yes
thank you
i have one last question could you help me?
No problem. And yeah!
How would i prove AB perpendicular to k it says Draw line AB and prove AB is perpendicular to k, then on the graph draw line j through paoint a, parallel to line k.
Well lines that are perpendicular have opposite slopes. So since the slope of line k is -2/3 the opposite of that is would be it flipped and positive So if line AB has a slope of 3/2 then they are perpendicular.
ok :)
Super simple right?
yes thank you.
Great!
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