Will give medals c:
http://prntscr.com/3bsl9w

Question

Will give medals c: 
http://prntscr.com/3bsl9w

anonymous · Answer

are you looking for the area? what polygon?

anonymous · Answer

The area c:

anonymous · Answer

i think it's triangle
the formula for a triangle is $\Large A= \frac{1}{2}bh$
substitute the given values into the formula and you're done :)

anonymous · Answer

Ohh okie c: Thanks

mathmale · Answer

Jacqui:  Wasn't there an illustration with this problem?

anonymous · Answer

Yes

mathmale · Answer

could you please share it here?

anonymous · Answer

I'm confused, Sorry .-.

anonymous · Answer

Do I post the question?

mathmale · Answer

I see you did share an illustration up front.  Was there no picture of a triangle or rectangle or other geometric figure connected with it?

anonymous · Answer

Unfortunately. No

anonymous · Answer

But I'm thinking it's $$560 ft ^{2}$$

anonymous · Answer

@mathmale

mathmale · Answer

If there's no illustration, J, then we'll have to make some assumptions.

Assumption #1:  the figure is a rectangle.  A=length times height = ??
Assumption #2   the figure is a parallelogram (see the diagram, below):|dw:1398012917187:dw|

mathmale · Answer

Assumption #3:   the figure is a triangle (see below)|dw:1398013004203:dw|

anonymous · Answer

So that will be 1120 divided by 1/2

anonymous · Answer

Which is $$560ft ^{2}$$

anonymous · Answer

Right?

mathmale · Answer

IF and only if your figure is a triangle, yes.   560 mm^2 would be perfect.

If your figure is a rectangle, the aera would be (80 mm )(14 mm)=1120 mm^2.

mathmale · Answer

I'd suggest that you move on to the rest of your math problems.

anonymous · Answer

kk and thank you soooo much c: