A clothing designer enters a competition to show ten original outfits at a fashion show. If the designer has 12 outfits to choose from how many ways to arrange the order in which he will show ten of them.

Question

A clothing designer enters a competition to show ten original outfits at a fashion show.  If the designer has 12 outfits to choose from how many ways to arrange the order  in which he will show ten of them.

kropot72 · Answer

This requires calculation of permutations:
$$12P10=\frac{12!}{(12-10)!}=\frac{12\times11\times10\times9\times8\times7\times6\times5\times4\times3}{2}=you\ can\ calculate$$

anonymous · Answer

I did everything but divide by 2.  I didn't know that I had to do that but my answer was so large.  I can't see your answer

kropot72 · Answer

The formula for finding the number of permutations of n different things taken r at a time is:
$$nPr=\frac{n!}{(n-r)!}$$
Can you use a calculator to work out the answer and post it?

anonymous · Answer

239,500,800/2=119750400  is this right?

kropot72 · Answer

$$\frac{12\times11\times10\times9\times8\times7\times6\times5\times4\times3\times2\times1}{2}=\frac{479001600}{2\times1}=239500800$$
Sorry, the numerator of my first post left out (*2*1).